Find the value of $x$ & $y$ in the equation $x - 3 y - 7 = 0$ & $3 x - 3 y - 1 = 0$ by the method of elimination.

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Solution

x-3y=7----(1)
3x-3y=1---(2)
on adding equation (1) &(2)
x-3y=7
3x-3y=1
(-)(+)(-)
_________
-2x=6
[x=-3]
Form eq (1)
3y=-3-7=-10
$[y = - \frac{10}{3}]$
$∴$ value of x is -3 & y is $\frac{- 10}{3}$

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