The correct option is A x=12,y=13
Let 1x be 'a' and 1y be 'b' (As x ≠ 0 & y ≠ 0).
We will get the equations as,
2a+3b=13 ....(1)
5a−4b=−2 ....(2)
Multiplying the first equation by 4 and the second equation by 3, we get
8a+12b=52
15a−12b=−6
Now adding the two equations, we get
23a=46
a=2
Substituting a=2 in equation (1), we get,
2×2+3b=13
3b=9
⇒b=3
Earlier, we have assumed that a=1x and b=1y
∴ x=12 and y=13