Find the value of (x+y)(x−y)(x2+y2) when x=3 and y=2
( - )
x3 + y3
( + )
x4 - y4
Given (x+y)(x−y)(x2+y2)
Substituting x=3 and y=2 we get
= (3+2)(3−2)(32+22)
= 5(9+4)
= 5(13)
= 65