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Question

Find the value of (x+y)(xy)(x2+y2) when x=3 and y=2


A

( - )

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B

x3 + y3

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C

( + )

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D

x4 - y4

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Solution

The correct option is D

x4 - y4


Given (x+y)(xy)(x2+y2)

Substituting x=3 and y=2 we get

= (3+2)(32)(32+22)

= 5(9+4)

= 5(9+4)

= 5(13)

= 65


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