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Factor of Polynomials

find the valu...

Question

find the value of x2+y2+z2 if x+y+Z=9 and XY+YZ+ZX=26

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Solution

we know that,
(x+y+z)^2 =x^2+y^2+z^2 + 2(xy+yz+zx)

9^2 = x^2+y^2+z^2 + 2* 26

81 = x^2+y^2+z^2 + 52

81 - 52 = x^2+y^2+z^2

ie,
x^2+y^2+z^2 = 29

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Similar questions

x + y + z = 10

x^{2} + y^{2} + z^{2} = 40

x y + y z + z x

x - y + z = 5

x^{2} + y^{2} + z^{2} = 49

, find the value of :

z x - x y - y z

x^{2} + y^{2} + z^{2} - x y - y z - z x = 0

then the value of

\frac{x + y}{z}

x + y + z = 10

x y + y z + z x = 20

, what is the value of

x^{2} + y^{2} + z^{2}

x + y + z = 0,

what will be the value of

\frac{x^{2} + y^{2} + z^{2}}{- (x y + y z + z x)} ?

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