Question

Find the value or values of $m$ for which $m(\hat{i}+\hat{j}+\hat{k})$ is a unit vector.

Answer 1

Magnitude of vector is $\sqrt{m^2+m^2+m^2}=\sqrt{3}m$

For the vector to be unit vector, magnitude of vector=1

$\sqrt{3}m=1$

therefore, $m=\frac{1}{\sqrt{3}}$