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Question

Find the value(s) of x for the relation 2y = (x+1)(x-1) at f(x) = 1 and determine whether it a function or not. Given that x is an independent variable and y is a dependent variable. Answer in Yes/No.


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Solution

The given relation is 2y=(x+1)(x1).
Given: f(x)=1
We need to evaluate x at y=1.
2(1)=(x+1)(x1)
2=xx+xx1
2+1=x2
x2=3

Here, x can have two values.
For x=3,3

Here, x is independent variable, having two sets of values that results to a single value, i.e., f(x)=1.

This relation is a function.





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