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First Principle of Differentiation

Find the valu...

Question

Find the value:-
${tan}^{2} x + {sin}^{2} y$ , if $x = 45^{o}, y = 30^{o}$

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Solution

${tan}^{2} x + {sin}^{2} y$
$= {tan}^{2} 45^{o} + {sin}^{2} 30^{o}$
$= 1 + \frac{1}{4} = \frac{5}{4}$

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