Question

Find the value to three places of decimals of each of the following. It is given that $\sqrt{2}=1.414,\sqrt{3}=1.732,\sqrt{5}=2.236$ and $\sqrt{10}=3.162$

$\left(vi\right)\frac{\sqrt{2}-1}{\sqrt{5}}$

Answer 1

Given: $\frac{\sqrt{2}-1}{\sqrt{5}}$
$=\frac{(\sqrt{2}-1)\times \sqrt{5}}{\sqrt{5}\times \sqrt{5}}$
$=\frac{\sqrt{10}-\sqrt{5}}{5}$
$=\frac{3.162-2.236}{5}$
$=\frac{0.926}{5}$
$=0.185$