Question

Find the value to three places of decimals of each of the following. It is given that $\sqrt{2}=1.414,\sqrt{3}=1.732,\sqrt{5}=2.236$ and $\sqrt{10}=3.162$

$\frac{2+\sqrt{3}}{3}$

Answer 1

Given that:-

$\sqrt{2}=1.414$

$\sqrt{3}=1.732$

$\sqrt{5}=2.236$

$\sqrt{10}=3.162$

$\therefore \frac{2+\sqrt{3}}{2}=\frac{2+1.732}{3}=\frac{3.732}{3}=1.124$

Hence, the correct answer is $1.124$.