Find the value using BODMAS- -1 -8-3 - 2-64 -4 -5-2 - 5-1-

The correct option is A 1 According to BODMAS the expressions inside the nbsp;brackets must be performed first. [1 × (8 3 × 2)] nbsp; 64 ÷ nbsp; [4 ...

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Standard V

Mathematics

BODMAS

Find the valu...

Question

Find the value using BODMAS.

$[1 \times (8 - 3 \times 2)] - 64 \div [4 \times (5 + 2 \times 5 + 1)] = ?$

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Solution

The correct option is A
1

According to BODMAS the expressions inside the brackets must be performed first.

$[1 \times (8 - 3 \times 2)] - 64 \div [4 \times (5 + 2 \times 5 + 1)] = [1 \times (8 - 6)] - 64 \div [4 \times (5 + 10 + 1)] = 2 - 64 \div 64 = 2 - 1 = 1$

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Find the value using BODMAS. [1×(8−3×2)]−64÷[4×(5+2×5+1)]=?

The correct option is A 1 According to BODMAS the expressions inside the brackets must be performed first. [1×(8−3×2)]−64÷[4×(5+2×5+1)]=[1×(8−6)]−64÷[4×(5+10+1)]=2−64÷64=2−1=1

Find the value using BODMAS.

$[1 \times (8 - 3 \times 2)] - 64 \div [4 \times (5 + 2 \times 5 + 1)] = ?$

The correct option is A
1

According to BODMAS the expressions inside the brackets must be performed first.

$[1 \times (8 - 3 \times 2)] - 64 \div [4 \times (5 + 2 \times 5 + 1)] = [1 \times (8 - 6)] - 64 \div [4 \times (5 + 10 + 1)] = 2 - 64 \div 64 = 2 - 1 = 1$