Find the valueof k for which the following system of equations has no solution:
2x + 3y - 5 = 0 and kx + 6y - 8 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 4
Given two equations $a_{1} x + b_{1} y = c_{1} a n d a_{2} x = b_{2} y = c_{2},$
the pair of equations will not have a solution if $\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}},$

Thus, for the given pair of equations to have no solution,
$\frac{2}{k} = \frac{3}{6} = \frac{- 5}{- 8}$
$\Rightarrow \frac{2}{k} = \frac{1}{2} \neq \frac{5}{8}$
$\Rightarrow k = 4$

Suggest Corrections

Similar questions

Find the value for k which each of the following systems of equations has a unique solution:

$2 x + 3 y - 5 = 0, k x - 6 y - 8 = 0.$

2 x + 3 y - 5 = 0, k x - 6 y - 8 = 0

2 x + 3 y - 5 = 0

k x - 6 y - 8 = 0

k

3 x - 4 y + 7 = 0

k x + 3 y - 5 = 0

2 x + 3 y - 5 = 0 k x - 6 y - 8 = 0

Join BYJU'S Learning Program