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Question

Find the values of a and b, if A= B, where A=[a+43b86] and B=[2a+2b2+28b25b].

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Solution

A=B
[a+43b86]=[2a+2b2+28b25b]

On equating the corresponding elements, we get,
a+4=2a+2 .......(1)
3b=b2+2 .......(2)
6=b25b ........(3)
From equation 1, we get,
a=2
And, from equation 2 and 3, we get,
b=2

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