Question

Find the values of $A$ and $B$ in the following

$12A$
$+6AB$
___________
$A09$
___________

• A. $A=8,B=4$
• B. $A=5,B=1$
• C. $A=9,B=1$
• D. $A=8,B=1$

Answer 1

The correct option is D $A=8,B=1$

From the given conditions:
$A+B=9$ .... (i)
$2+A=0$ ...(ii) and
$6+1+$ carry-over $=A$ ...(iii)
From (ii), $A$ can only be $8$ to make the units digit of the sum of $2$ numbers as $0$
hence, from (i) $A+B=9$
$B=9-A$ or
$B=9-8=1$

option D