Question

Find the values of A, B and C from the given options, if

A B

x 6
_____

C 8 8

• A. A = 5, B = 8, C = 1
• B. A = 4, B = 7, C = 2
• C. A = 4, B = 8, C = 2
• D. A = 3, B = 9, C = 2

Answer 1

The correct option is C A = 4, B = 8, C = 2

Let us look at B first.
We have been given that 6 x B gives a number with 8 in the ones place.
This means B could be 3 or 8.
(i) If B = 3,
A3 x 6 = C88

3 x 6 = 18 and
A x 6 + 1 (carryover) = C8

If A x 6 gives a number with units digit 7 then by adding 1 (carryover) we get 8 ( units place of C8).

There is no such digit that when multiplied by 6 gives 7 in its units place.

So B = 3 is ruled out.

(ii) If B = 8,

A8 x 6 = C88

8 x 6 = 48
A x 6 + 4 (carryover) = C8

This means that A is a number which when multiplied with 6 gives a number with 4 in the ones place and when the result is added with the carried 4 gives 8 in the ones place of C8.
So, possible values of A are 4, 9

6 $\times$ 4 + 4 = 28
So, A = 4 and C = 2

6 $\times$ 9 + 4 = 58
So, A = 9 and C = 5

From the given options: A = 4 and C =2 with B = 8

4 8

x 6
____

2 8 8