Question

Find the values of $\angle a$ $\angle b$ in the figure given below.

Answer 1

BCD is linear pair

$\begin{array}{c}\angle b+{88}^0={180}^0\\ \angle b={180}^0-{88}^0={92}^0\end{array}$

Sum of angle of $\Delta ABC$

$\begin{array}{c}{30}^0+{92}^0+a^0={180}^0\\ a^0={180}^0-{30}^0-{92}^0={58}^0\end{array}$