Question

Find the values of $\sin (\frac{\pi }{3}-{\sin }^{-1}(-\frac{1}{2}))$

• A. $\frac{1}{2}$
• B. $\frac{1}{3}$
• C. $\frac{1}{4}$
• D. $1$

Answer 1

The correct option is D $1$

The value of $\sin (\frac{\pi }{3}-{\sin }^{-1}(-\frac{1}{2}))$

$=\sin (\frac{\pi }{3}-(-\frac{\pi }{6}))$

$=\sin \frac{\pi }{2}$

$=1$