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Question

Find the values of each of the following:
(i) tan-12 cos2 sin-112
(ii) cottan-1a+cot-1a
(iii) cossec-1x+cosec-1x, x 1

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Solution

(i) Let sin-112=y
Then,
siny=12

tan-12cos2sin-112=tan-12cos2y=tan-121-2sin2y cos2x=1-2sin2x=tan-121-2×14 siny=12=tan-12×12=tan-11=π4

tan-12cos2sin-112=π4

(ii)

We havecottan-1a+cot-1a=cotπ2 tan-1x+cot-1x=π2=0

cottan-1+cot-1a=0

(iii)
We have
cossec-1x+cosec-1x=cosπ2 sec-1x+cosec-1x=π2=0

cossec-1x+cosec-1x=0 , |x|1

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