Question

Find the values of k for which the following equation real and equal roots. $(k+1)x^2-2(k-1)x+1=0$

Answer 1

Given $(k+1)x^2-2(k-1)x+1=0$ has equal roots

$⟹$Discriminant$=0$

$⟹(-2(k-1){)}^2-4(k+1)=0$

$⟹4(k^2-2k+1)-4k-4=0$

$⟹k^2-3k=0⟹k=0,3$