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Byju's Answer
Standard X
Mathematics
Nature of Roots
Find the valu...
Question
Find the values of
k
for which the following equations have real roots.
k
x
(
x
−
3
)
+
18
=
0
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Solution
k
x
(
x
−
3
)
+
18
=
0
k
x
2
−
3
k
x
+
18
=
0
and
k
≠
0
This is in the form of
a
x
2
+
b
x
+
c
=
0
Here
a
=
k
,
b
=
−
3
k
,
c
=
18
For the equation to have real roots ,
discriminant
≥
0
⟹
(
−
3
k
)
2
−
4
(
k
)
(
18
)
≥
0
9
k
2
-
(
72
)
(
k
)
≥
0
k
(
k
−
8
)
≥
0
k
ϵ
(
8
,
∞
)
&
k
ϵ
(
−
∞
,
0
)
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