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Question

Find the values of k for which the following equations have real roots.
kx(x3)+18=0

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Solution

kx(x3)+18=0
kx23kx+18=0 and k0
This is in the form of ax2+bx+c=0
Here a=k,b=3k,c=18
For the equation to have real roots ,
discriminant 0(3k)24(k)(18)0
9k2-(72)(k)0
k(k8)0
kϵ(8,) & kϵ(,0)

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