wiz-icon
MyQuestionIcon
MyQuestionIcon
9
You visited us 9 times! Enjoying our articles? Unlock Full Access!
Question

Find the values of k for which the given equation has real roots
5x2kx+1=0

Open in App
Solution

The given equation is 5x2kx+1=0

Here, a=5,b=k,c=1

D=b24ac=(k)24×5×1=k220

The given equation will have real roots if
D0

k2200k20ork20[x2a20xaorxa]

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Nature of Roots
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon