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Question

Find the values of k for which the quadratic equation 9x23kx+k=0 has equal roots.

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Solution

We know that D=0 then the equation has equal and real roots

D=b24ac=0

a=9,b=3k,c=k

Subsitute the values we get,

(3k)24×9×k=0

9k236k=0

9k2=36k

9k(k4)=0

k=0ork=4


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