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Byju's Answer
Standard XII
Mathematics
Area of Triangle with Coordinates of Vertices Given
Find the valu...
Question
Find the values of
K
if Area of the triangle is
4
sq. units and vertices are
(
k
0
)
(
4
0
)
(
0
2
)
using determinants.
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Solution
1
2
∣
∣ ∣
∣
K
0
1
4
0
1
0
2
1
∣
∣ ∣
∣
=
±
4
K
=
(
0
−
2
)
−
0
(
0
)
+
1
(
8
)
=
±
8
−
2
K
+
8
=
±
8
−
2
K
=
8
−
8
−
2
K
=
0
K
=
0
or
−
2
K
=
−
8
−
8
2
K
=
16
K
=
8
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Q.
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