CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the values of magnetic field between pates of capacitor at distance 1 m from centre, where electric field varies by 1010 V/m per second.

A
5.56×108 T
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
5.56×103 T
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5.56 μT
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5.56 T
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 5.56×108 T
Distance =1m.(d)
electric field varies by=1010V/m
Tension =dEdt=1010
B=μ0ϵ0r2×dEdt
=4π×103×8.854×1012×12×1010
=5.56×108T

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Maxwell's Equation
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon