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Question

Find the values of p for which the quadratic equation 2x^2+px+8=0 has real roots.

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Solution

2x^2+px+8=0

for real root

b2-4ac >0

p2-4.2.8 >0 ( here substitute b for p as in the givien equation )

p2 - 64 >0

p2>64

p>±8


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