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Question

Find the values of p for which the quadratic equation 4x2+px+3=0 has equal roots.
If α and β are the zeros of the polynomial 6y2-7y+2,find a quadratic polynomial whose zeros are 1αand 1β.

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Solution

10.The given quadratic equation is,4x2 + px + 3 = 0Now, a = 4; b = p; c = 3Now, D = b2 - 4ac =p2 - 48For equal roots, D = 0p2 - 48 = 0p2 = 48p = ±4311.Let py = 6y2 - 7y + 2Now, α + β = -coefficient of ycoefficient of y2 = 76Now, αβ = constant termcoefficient of y2 = 26 = 13Now, 1α and 1β are the zeroes of required polynomial.Sum of zeroes of required polynomial, S = 1α + 1β=α + βαβ=7/61/3=76×31 = 72Product of zeroes of required polynomial, P = 1α × 1β = 1αβ = 3Now, required polynomial is,fy = kx2-Sx + P, where k is a non zero real number=kx2 - 7x2 + 3=k22x2 - 7x + 6=2x2 - 7x + 6 On taking k = 2

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