Find the values of the following:
a) $2^{0}$ + $3^{0}$ + $4^{0}$
b) $2^{0}$ × $3^{0}$ × $4^{0}$
[2 marks]

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Solution

a) $2^{0}$ + $3^{0}$ + $4^{0}$

= 1 + 1+ 1 = 3
[1 mark]

b) $2^{0}$ × $3^{0}$ × $4^{0}$

= 1 × 1 × 1 = 1
[1 mark]

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