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Question

Find the values of the following determinants
2i3ii32i5 where i=1.

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Solution

2i3ii32i5
=(2i×2i5)(i3×3i)
=4i6(3i2)
=4+3
=7.

1072120_1160080_ans_42f0620479cb4af9b60031601ffa9b31.png

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