Find the values of the following determinants 2i -3i i 3 -2 i 5 where i-1-

2i amp; 3i i^3 amp; 2i^5 =(2i× 2i^5) (i^3× 3i) = 4i^6 (3i^2) =4+3 =7 . ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Determinant

Find the valu...

Question

Find the values of the following determinants
$∣ ∣ ∣ \begin{matrix} 2 i & - 3 i i^{3} & - 2 i^{5} \end{matrix} ∣ ∣ ∣$ where $i = \sqrt{- 1}$ .

Open in App

Solution

Suggest Corrections

Similar questions

i = \sqrt{- 1}

∣ ∣ ∣ \begin{matrix} 2 i & - 3 i i^{3} & - 2 i^{5} \end{matrix} ∣ ∣ ∣

i = \sqrt{- 1} .

∣ ∣ ∣ \begin{matrix} 2 i & - 3 i i^{3} & {- 2 i}^{5} \end{matrix} ∣ ∣ ∣

∣ ∣ ∣ \begin{matrix} 1 + 3 i & i - 2 - i - 2 & 1 - 3 i \end{matrix} ∣ ∣ ∣

∣ ∣ ∣ \begin{matrix} 2 i & - 3 i i^{3} & - 2 i^{3} \end{matrix} ∣ ∣ ∣

i = \sqrt{- 1}

∣ ∣ ∣ \begin{matrix} 2 i & - 3 i i^{3} & - 2 i^{s} \end{matrix} ∣ ∣ ∣

i = \sqrt{- i}

\frac{3 + \sqrt{2 i} - (3 \sqrt{2 i})}{(5 + 2 i) (5 - 2 i)}

Join BYJU'S Learning Program