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Question

Find the values of the following
(i) 2 tan 2 45° + cos 2 30 - sin 2 60°
(ii) 4cot 2 45° - sec 2 60° + cosec 2 30°+cot 90°

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Solution

(i)
2tan245° +cos2 30°-sin2 60°=2×12+322-322= 2+0 = 2

(ii)
4cot2 45°-sec260°+cosec230° +cot 90°= 4×12 - 22+ 22+0= 4+0 = 4

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