Question

Find the values of the following polynomial.
$p\left(x\right)=2x^2+\frac{1}{4}x+13$, when $x=-1$

Answer 1

In the given polynomial $p\left(x\right)=2x^2+\frac{1}{4}x+13$, substitute $x=-1$ as shown below:

$p(-1)=(2\times (-1{)}^2)+(\frac{1}{4}\times (-1\left)\right)+13=(2\times 1)-\frac{1}{4}+13=15-\frac{1}{4}=\frac{60-1}{4}=\frac{59}{4}$

Hence, $p(-1)=\frac{59}{4}$.