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Sign of Trigonometric Ratios in Different Quadrants

Find the valu...

Question

Find the values of the following:
$sin 120^{o}$

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Solution

$sin 120^{o} = sin (180^{o} - 60^{o})$
$= sin 60^{o}$
$= \frac{\sqrt{3}}{2}$

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Q. Find the value of

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Q. Assertion :Consider the following statements.
The value of

sin 120^{o}

can be derived by taking

θ = 240^{o}

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2 sin \frac{θ}{2} = \sqrt{1 + sin θ} - \sqrt{1 - sin θ}

. Reason: The angles A, B, C and D of any quadrilateral ABCD satisfy the equation

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