Find the values of the following using the formula of the square of a binomial.

(3) 59²

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Solution

59²
or 59 = 60 − 1
59² = (60 − 1)²
Thus, we can use the identity (a − b)² = a² − 2ab + b² .
∴ 59² = (60 − 1)²
= (60)² − 2 (60) (1) + (1)²
= 3600 − 120 + 1
= 3600 + 1 − 120
= 3601 − 120
= 3481

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