Question

Find the values of the letters [3 MARKS]

$\begin{array}{c}AB\\ \times 6\\ BBB\end{array}$

Answer 1

Concept: 1 Mark
Application: 2 Marks

For the last digit of AB and BBB to be same, B must be either 6 or 4.

If B = 6, BBB = 666.

Now let A = 9.

We find that $96\times 6(AB\times 6)$ is less than 600 because $100\times 6$ is 600.

A can have no higher value than 9.

Hence, BBB can never be 666 and B cannot be 6.

Thus B = 4. For B = 4, BBB is 444.

When A = 7 and B = 4, BBB is 444.

This satisfies the condition.