Question

Find the values of the trigonometric ratio
$\tan \theta =11$

Answer 1

According to question,

$tanA=\frac{11}{1}=\frac{P}{B}$

Let hypotenuse , $H=3k$

So, perpendicular,$P=2k$

$P^2+B^2=H^2$

$H^2=P^2+B^2$

$=(11k{)}^2+(1k{)}^2$

$=122k^2$

$H=\sqrt{122}k$

$cosA=\frac{B}{H}$
$=\frac{1}{\sqrt{122}}$

$cotA=\frac{B}{P}$
$=\frac{1}{11}$

$cosecA=\frac{H}{P}$
$=\frac{\sqrt{122}}{11}$

$secA=\frac{H}{B}$
$=\frac{\sqrt{122}}{1}$

$sinA=\frac{P}{H}$

$=\frac{11}{\sqrt{122}}$