Question 125
Find the values of x and y in the given figure.
In ΔTQS, ∠T+∠Q+∠S=180∘ [angle sum property of a triangle]
⇒50∘+30∘+∠1=180∘⇒80∘+∠1=180∘⇒∠1=180∘−80∘=100∘
Now, ∠1+x=180∘ [linear pair]
⇒100∘+x=180∘⇒x=180∘−100∘⇒x=80∘
In ΔTSR,x+45∘+∠2=180∘ [angle sum property of a triangle]
⇒∠2=180∘−80∘−45∘=55∘
Now, 50∘+∠2+y=180∘ [linear pair]
⇒y=180∘−50∘−55∘=75∘