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Question

Find the values of x and y which satisfy the equations (x,yR)
(x+2y)+(2x3y)i+4i=5

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Solution

(x+2y)+(2x3y)i+4i=5
(x+2y)+(2x3y)i=54i
Comparing the real and imaginary part of both the sides we have,
x+2y=5
2x3y=4
2(x+2y)=5×2
2x+4y=10
±2x34=4
solving above equations we get,
+7y=14
y=2
puttinh values in first equation we have,
x+2×2=5
x+4=5
x=54=1

So, x=1 and y=2


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