Find the values of x for which 3 x x 1-3 2 4 1-

Given #160; 3 amp; x x amp; 1 = 3 amp;2 4 amp;1 Solving the determinants, we get: 3 x ^ 2 =3 8 x ^ 2 =8 x=± 2√( 2 ) ...

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Find the values of $x$ for which $∣ ∣ ∣ \begin{matrix} 3 & x x & 1 \end{matrix} ∣ ∣ ∣ = ∣ ∣ ∣ \begin{matrix} 3 & 2 4 & 1 \end{matrix} ∣ ∣ ∣$ .

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∣ ∣ ∣ \begin{matrix} 3 & x x & 1 \end{matrix} ∣ ∣ ∣ = ∣ ∣ ∣ \begin{matrix} 3 & 2 4 & 1 \end{matrix} ∣ ∣ ∣

∣ ∣ ∣ \begin{matrix} 3 & x x & 1 \end{matrix} ∣ ∣ ∣ = ∣ ∣ ∣ \begin{matrix} 3 & 2 4 & 1 \end{matrix} ∣ ∣ ∣

|\begin{matrix} 2 & 4 \\ 5 & 1 \end{matrix}| = |\begin{matrix} 2 x & 4 \\ 6 & x \end{matrix}|

|\begin{matrix} 2 & 3 \\ 4 & 5 \end{matrix}| = |\begin{matrix} x & 3 \\ 2 x & 5 \end{matrix}|

|\begin{matrix} 3 & x \\ x & 1 \end{matrix}| = |\begin{matrix} 3 & 2 \\ 4 & 1 \end{matrix}|

|\begin{matrix} 3 x & 7 \\ 2 & 4 \end{matrix}| = 10

|\begin{matrix} 2 & 4 \\ 5 & 1 \end{matrix}| = |\begin{matrix} 2 x & 4 \\ 6 & x \end{matrix}|

|\begin{matrix} 2 & 3 \\ 4 & 5 \end{matrix}| = |\begin{matrix} x & 3 \\ 2 x & 5 \end{matrix}|

|\begin{matrix} 3 & x \\ x & 1 \end{matrix}| = |\begin{matrix} 3 & 2 \\ 4 & 1 \end{matrix}|

|\begin{matrix} 3 x & 7 \\ 2 & 4 \end{matrix}| = 10

|\begin{matrix} x + 1 & x - 1 \\ x - 3 & x + 2 \end{matrix}| = |\begin{matrix} 4 & - 1 \\ 1 & 3 \end{matrix}|

|\begin{matrix} 2 x & 5 \\ 8 & x \end{matrix}| = |\begin{matrix} 6 & 5 \\ 8 & 3 \end{matrix}|

(\begin{matrix} 3 & y x & 1 \end{matrix} ∣ ∣ ∣ = (\begin{matrix} 3 & 2 4 & 1 \end{matrix} ∣ ∣ ∣

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