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Byju's Answer
Standard XII
Mathematics
Determinant
Find the valu...
Question
Find the values of
x
for which
∣
∣
∣
3
x
x
1
∣
∣
∣
=
∣
∣
∣
3
2
4
1
∣
∣
∣
.
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Solution
Given
∣
∣
∣
3
x
x
1
∣
∣
∣
=
∣
∣
∣
3
2
4
1
∣
∣
∣
Solving the determinants, we get:
3
−
x
2
=
3
−
8
x
2
=
8
x
=
±
2
√
2
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0
Similar questions
Q.
Find values of
x
for which
∣
∣
∣
3
x
x
1
∣
∣
∣
=
∣
∣
∣
3
2
4
1
∣
∣
∣
Q.
If
∣
∣
∣
3
x
x
1
∣
∣
∣
=
∣
∣
∣
3
2
4
1
∣
∣
∣
then x is equal to
Q.
Find the values of x, if
(i)
2
4
5
1
=
2
x
4
6
x
(ii)
2
3
4
5
=
x
3
2
x
5
(iii)
3
x
x
1
=
3
2
4
1
(iv) If
3
x
7
2
4
=
10
, find the value of x.
Q.
Find the values of x, if
(i)
2
4
5
1
=
2
x
4
6
x
(ii)
2
3
4
5
=
x
3
2
x
5
(iii)
3
x
x
1
=
3
2
4
1
(iv) If
3
x
7
2
4
=
10
, find the value of x.
(v)
x
+
1
x
-
1
x
-
3
x
+
2
=
4
-
1
1
3
(vi)
2
x
5
8
x
=
6
5
8
3
Q.
If
(
3
y
x
1
∣
∣
∣
=
(
3
2
4
1
∣
∣
∣
, where x and y are natural numbers, then possible values of x and y are:
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Determinant
Standard XII Mathematics
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