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Question

Find the values of x, if

(i) 2451 = 2x46x

(ii) 2345=x32x5

(iii) 3xx1=3241

(iv) If 3x724=10, find the value of x.

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Solution

(i)
Given:2451 = 2x46x2 - 20 = 2x2 - 24-18 = 2x2 - 242x2 = 6x2= 3x = ±3

(ii)
Given: 2345 = x32x510 - 12 = 5x - 6x-2 = -x x = 2

(iii)
Given: 3xx1 = 32413 - x2 = 3 - 8-x2 = -8x2 = 8x = ±22

(iv)
Given: 3x724 = 1012x - 14 = 1012x = 24x = 2

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