Find the values of x in each of the following

$(i) l o g_{2} x = 3$

$(i i) l o g_{81} x = \frac{3}{2}$

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Solution

Find the values of x in each of the following

(i) $l o g_{2} x = 3 \Rightarrow x = 2^{3} = 8$

(ii) $l o g_{81} x = \frac{3}{2} \Rightarrow x = (81)^{\frac{3}{2}}$

$\Rightarrow x = (3^{4})^{\frac{3}{2}}$

$\Rightarrow x = 3^{6} = 729$

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{log}_{2} (x + y) = 3

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x

y

Find the solution set in ${log}_{2} (x - 1) + {log}_{2} (x - 2) > 1$

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