Question

Find the values of x such that $x^2-5x-6>0$ and $x^2-4x+3\le 0$?

• A. -1≤x≤2
• B. 0≤x≤4
• C. 1≤x≤3
• D. None of these

Answer 1

The correct option is D None of these

Conventional Method:-

Factorize the equations

$x^2-6x+x-6>0$

(x-6)(x+1) $>$0

x $<$ -1 and x $>$ 6

$x^2-4x+3\le 0$

$x^2-3x-x+3\le 0$

x(x-3)-1(x-3) $\le$ 0

(x-1)(x-3) $\le$ 0

1 $\le$ x $\le$ 3

There is no common solution for these equations.