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Question

Find the values of 'x' which satisfies both the equations
(ab)x2+(bc)x+(ca)=0 and (ca)x2+(bc)x+(ab)=0

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Solution

(ab)x2+(bx)x+(ca)=0
(cb)x2+(bc)x+(ab)=0
has common root 'x'
Adding 2 equation we get a new equation which also has root 'X'.
(cb)x22(cb)x+(cb)=0
(on adding 2 equation)
x22x+1=0
(x1)2=01

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