Find the values of x, which satisfy the inequation −256<12−2x3≤2,x∈W.
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Solution
Given: −256<12−2x3≤2 ⇒−176<3−4x6≤2 Multiplying throughout by 6 ⇒−17<3−4x≤12 −17<3−4x and 3−4x≤12 ⇒4x<3+17⇒3−12≤4x ⇒4x<20⇒−9≤4x ⇒x<5⇒−94<x {5>x≥−94} Hence, the solution set is {x:x∈W,−94≤x<5}
Since x is a whole number, ∴ Values of x are {0,1,2,3,4}