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Question

Find the values of x,y and z if [x+2635z]=[5y2+y320]

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Solution

[x+2635z]=[5y2+y320]
x+2=55z=20
x=52z=20/5
x=7z=4
y2+y=6
y2+y6=0
y2+3y2y6=0
y(y+3)2(y+3)=0
(y+3)=0(y2)=0
So y=3, y=2

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