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Question
Find the values of y for which the distance between the points P (2, - 3) and Q (10, y) is 10 units.
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Solution
It is given that the distance between (2, - 3) and (10, y) is 10.
Therefore, √(2−10)2+(−3−y)2=10
√(−8)2+(3+y)2=10
64+(y+3)2=100
(y+3)2=36
y+3=±6
y+3=+6 or y+3=−6
Therefore, y=3 or −9
Therefore, √(2−10)2+(−3−y)2=10
√(−8)2+(3+y)2=10
64+(y+3)2=100
(y+3)2=36
y+3=±6
y+3=+6 or y+3=−6
Therefore, y=3 or −9
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