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Algebraic Identities

Find the valu...

Question

Find the values of y if $y = x^{2} - 1$ and x = 2y - 1.

((5/4), 0)

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(-(5/4), 0)

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(-(5/4), (5/4))

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(0, (1/4))

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Solution

The correct option is A
((5/4), 0)

$y = x^{2} - 1$ ----- (i)
x = 2y - 1
Putting the value of x in (i)
$y = (2 y - 1)^{2} - 1$
$4 y^{2} - 5 y = 0$
y(4y-5)=0.
y=0
$y = \frac{5}{4}$

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