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Byju's Answer
Standard XII
Mathematics
Equation of Perpendicular from a Point on a Line
Find the vect...
Question
Find the vector and cartesian eqns of a plane containing the two lines.
→
r
=
(
2
^
i
+
^
j
−
3
^
k
)
+
λ
(
^
i
+
2
^
j
+
5
^
k
)
and
→
r
=
(
3
^
i
+
3
^
j
+
2
^
k
)
+
μ
(
3
^
i
−
2
^
j
+
5
^
k
)
Open in App
Solution
→
Normal vector of plane
would be perpendicular to
both the lines say
l
1
&
l
2
⇒
parallel to
→
l
1
×
→
l
2
→
l
1
×
→
l
2
=
∣
∣ ∣ ∣
∣
^
i
^
j
^
k
1
2
5
3
−
2
5
∣
∣ ∣ ∣
∣
=
20
^
i
+
10
^
j
−
6
^
k
and the plane passes through
(
2
,
1
,
−
3
)
(line
l
1
)
⇒
its equation :
(
→
r
−
→
a
)
→
n
=
0
⇒
→
r
.
→
n
=
→
a
.
→
n
⇒
→
r
(
20
^
i
+
10
^
j
−
8
^
k
)
=
40
+
10
+
24
=
74
⇒
20
x
+
10
y
−
8
z
=
74
Suggest Corrections
0
Similar questions
Q.
Find shortest distance between lines
→
r
=
^
i
+
2
^
j
+
3
^
k
+
λ
(
2
^
i
+
^
j
+
4
^
k
)
and
→
r
=
2
^
i
+
4
^
j
+
5
^
k
+
μ
(
3
^
i
+
4
^
j
+
5
^
k
)
Q.
If
→
r
=
3
^
i
+
2
^
j
−
5
^
k
,
→
a
=
2
^
i
−
^
j
+
^
k
,
→
b
=
^
i
+
3
^
j
−
2
^
k
and
→
c
=
−
2
^
i
+
^
j
−
3
^
k
such that
→
r
=
l
→
a
+
m
→
b
+
n
→
c
, then
Q.
Find the shortest distance between the lines
→
r
=
(
4
^
i
−
^
j
)
+
λ
(
^
i
+
2
^
j
−
3
^
k
)
and
→
r
=
(
^
i
−
^
j
+
2
^
k
)
+
μ
(
^
i
+
4
^
j
−
5
^
k
)
Q.
Find the angle between the planes whose vector equations are
→
r
.
(
2
^
i
+
2
^
j
−
3
^
k
)
=
5
and
→
r
.
(
3
^
i
−
3
^
j
+
5
^
k
)
=
3
Q.
Find the angle, between the planes whose vector equations are
→
r
⋅
(
2
^
i
+
2
^
j
−
3
^
k
)
=
5
and
→
r
⋅
(
3
^
i
−
3
^
j
+
5
^
j
+
5
^
k
)
=
3
.
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