Question

Find the vector equation for the line passing through the points $(-1,0,2)$ and $(3,4,6)$.

Answer 1

(-1,0,2) & (3,4,6)

Direction cosines : (3+1,4+0,6-2)

ie (4,4,4)

$E{q}^2\Rightarrow \left(\frac{x-4}{4}\right)=\left(\frac{y-4}{4}\right)=\left(\frac{z-6}{4}\right)$

$\Rightarrow [\frac{(x-3)}{1}=\frac{(y-4)}{1}=\frac{(z-6)}{1}]$