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Byju's Answer
Standard XII
Mathematics
Equation of a Plane Parallel to a Given Plane
Find the vect...
Question
Find the vector equation of a line passing through the point (2, 3, 2) and parallel to the line
r
→
=
-
2
i
^
+
3
j
^
+
λ
2
i
^
-
3
j
^
+
6
k
^
.
Also find the distance between these lines.
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Solution
Vector equation of a line passing through (2, 3, 2) and parallel to the line
r
→
=
-
2
i
^
+
3
j
^
+
λ
2
i
^
-
3
j
^
+
6
k
^
has direction ratios (2, −3, 6)
Hence, its equation is
r
→
=
2
i
^
+
3
j
^
+
2
k
^
+
λ
2
i
^
-
3
j
^
+
6
k
^
Hence, distance between
r
→
=
a
→
1
+
λ
b
→
1
and
r
→
=
a
→
2
+
μ
b
→
1
=
a
→
2
+
μ
b
→
1
is
d
=
a
→
1
-
a
→
2
×
b
→
b
→
Here
,
a
→
1
=
-
2
i
^
+
3
j
^
,
a
→
2
=
2
i
^
+
3
j
^
+
2
k
^
and
b
→
=
2
i
^
-
3
j
^
+
6
k
^
i
.
e
.
d
=
-
4
i
^
-
2
k
^
×
2
i
^
-
3
j
^
+
6
k
^
2
2
+
-
3
2
+
6
2
a
→
1
-
a
→
2
×
b
→
=
i
^
j
^
k
^
-
4
0
-
2
2
-
3
6
=
i
^
-
6
-
j
^
-
24
+
4
+
k
^
12
i
.
e
a
→
1
-
a
→
2
×
b
→
=
-
6
i
^
+
20
j
^
+
12
k
^
∴
d
=
-
6
i
^
+
20
j
^
+
12
k
^
4
+
9
+
36
=
-
6
i
^
+
20
j
^
+
12
k
^
7
=
2
-
3
i
^
+
10
j
^
+
6
k
^
7
=
2
7
9
+
100
+
36
=
2
7
×
145
Suggest Corrections
2
Similar questions
Q.
Find the distance between the lines l
1
and l
2
given by
r
→
=
i
^
+
2
j
^
-
4
k
^
+
λ
2
i
^
+
3
j
^
+
6
k
^
and
,
r
→
=
3
i
^
+
3
j
^
-
5
k
^
+
μ
2
i
^
+
3
j
^
+
6
k
^
Q.
Find the equation of the line passing through the point (2, −1, 3) and parallel to the line
r
→
=
i
^
-
2
j
^
+
k
^
+
λ
2
i
^
+
3
j
^
-
5
k
^
.
Q.
Determine the equation of straight line passing through the point with position vector
i
−
3
j
+
k
and parallel to the vector,
2
i
+
3
j
−
4
k
.
Q.
The distance of the point
B
with position vector
i
+
2
j
+
3
k
from the line passing through the point
A
with position vector
4
i
+
2
j
+
2
k
and parallel to the vector
2
i
+
3
j
+
6
k
is
Q.
A plane passing through the point(-1,1,1) is parallel to the vector
2
ˆ
i
+
3
ˆ
j
−
7
ˆ
k
and line
r
=
(
ˆ
i
−
2
ˆ
j
−
ˆ
k
)
+
λ
(
3
ˆ
i
−
8
ˆ
j
+
2
ˆ
k
)
. Find the vector equation of the plane.
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