Question

Find the vector equation of the line joining(1,2,3) and (-3,4,3) .

Answer 1

$\begin{array}{c}\overrightarrow{r}={\overrightarrow{r}}_0+t\overrightarrow{v}\\ \overrightarrow{r}=\left[1,2,3\right]+t\left(-4,2,0\right)\\ =1+\left(-4t\right),2+2t,3\\ \overrightarrow{r}=1-4t,2+2t,3\end{array}$